(1/2y^2-1/3y)(12y+3/5)

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Solution for (1/2y^2-1/3y)(12y+3/5) equation: 


y in (-oo:+oo)

((1/2)*y^2-((1/3)*y))*(12*y+3/5) = 0

((1/2)*y^2+(-1/3)*y)*(12*y+3/5) = 0

(1/2*y^2-1/3*y)*(12*y+3/5) = 0

1/2*y^2-1/3*y = 0

y*(1/2*y-1/3) = 0

1/2*y-1/3 = 0 // + 1/3

1/2*y = 1/3 // : 1/2

y = 1/3/1/2

y = 2/3

y*(y-2/3) = 0

y*(y-2/3)*(12*y+3/5) = 0

( 12*y+3/5 )

12*y+3/5 = 0 // - 3/5

12*y = -3/5 // : 12

y = -3/5/12

y = -1/20

( y-2/3 )

y-2/3 = 0 // + 2/3

y = 2/3

( y )

y = 0

y in { -1/20, 2/3, 0 }

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